Home/ Questions/How can i handle - terminate called after throwing an instance of 'std::out_of_range'?
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Louis Gerard
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Asked: 2022-05-18T10:18:46+00:00 In:

How can i handle – terminate called after throwing an instance of ‘std::out_of_range’?

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I’m building a new program, but when I run it, an error pops up. The error displayed is as follows:

'std::out_of_range' what(): vector:_M_range_check

I have tried several workarounds, but they still do not get the desired results. If you have come across this situation and have a solution for the “terminate called after throwing an instance of ‘std::out_of_range’” problem, pls let me know. Here is what I do:

#include <vector>
 #include <iostream>
 #include <random>
 #include <time.h>
 
 using namespace std;
 using std::vector;
 
 int main()
 {
 
 vector<int> deck;
 vector<int> nums;
 default_random_engine eng(time(0));
 uniform_int_distribution<int> dis(0, 51);
 
 int pos1;
 int pos2;
 int num1;
 int num2;
 int i;
 int n;
 int m;
 
 for (i = 0; i < 52; i++)
 {
  nums.push_back(i);
 
 }
 
 for(int j = 0; j < 52; j++)
 {
  cout << nums.at(i) << "\n";
 }
 
 
 for(n = 0; n < 50; n++)
 {
  pos1 = dis(eng);
  pos2 = dis(eng);
 
  cout << pos1 << "\n" << pos2 << "\n";
 
  num1 = deck.at(pos1);
  num2 = deck.at(pos2);
 
 }
 
 }

Thanks!

std::out_of_range
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2 Answers

  1. Best Answer
    Expert

    The cause: This appears to be a typo, and you should use the variable ‘j’ in the second loop instead. Following the first loop,

    for (i = 0; i < 52; i++)
{
    nums.push_back(i);
}

    Because the variable ‘i’ has the value 52, it appears that using nums.at(i) will result in a std::out of range, because nums only has 52 values, starting at index 0.

    for(int j = 0; j < 52; j++)
{
    cout << nums.at(i) << "\n";
}

    The solution: To solve this problem, you should replace the argument of at() with ‘j’

    for(int j = 0; j < 52; j++)
{
    cout << nums.at(j) << "\n";
}
    • 10

  2. You can access deck elements here: 

    num1 = deck.at(pos1);
num2 = deck.at(pos2);

    But it is empty. Before making these calls, you must fill it. std::vector::size can be used to determine if a vector has been filled with std::vector::empty. For more information, see this HTML14 reference.

    • 8

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