The circuit diagram below shows two emf sources and a bulb connected in parallel. Also connected…

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James Portman

Asked: April 13, 20222022-04-13T04:46:59+00:00 2022-04-13T04:46:59+00:00In: Physics

The circuit diagram below shows two emf sources and a bulb connected in parallel. Also connected…

30

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The circuit diagram below shows two emf sources and a bulb
connected in parallel. Also connected in the circuit is a resistor
with resistance R = 0.2 ? . The resistance of the bulb is Rb = 0.5
? , and each of the sources has internal resistance: r1 = 0.025 ?
and r2 = 0.02 ? .

If E1 = 13.0 V and E2 = 5.0 V , calculate the current I1 flowing
in emf source E1.

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The%20circuit%20diagram%20below%20shows%20two%20emf%20sources%20and%20a%20bulb%20connected%20in%20parallel.%20Also%20connected...

r2 と2

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1 Answer

Charlotte O'Sullivan
2022-04-13T04:49:55+00:00Added an answer on April 13, 2022 at 4:49 am
The circuit diagram can be seen in the following figure: 12 8 Apply Kirchhoffs junction rule and the circuit will give you 1-11-1. Next, apply the Kirchhoffs loop rules to the lower loop of circuit. We get 13 V-Il (0.25 O)-4(0.02O)-5 V-11 (0.2O)=0 8-02251,0.021,-0 8-02251,0.021,-0 8-02251,0.021,-0 8-02251,0.021, -0)5+0.521) (0.5 O)5+0.5 O)1 +0.5 O)1 (0.5 O)5+0.5 O)5+0.5 O)5+0.5210.5 O)5 = s 5 = 0.511-12 (0.5 O)5+5 O)1 (0.5 O)1-0)5+0.5 O-0)5+0.511-12) (0.5 O)5 O)5+0.5 O-0)5+0.5 O-0 5+0.511-12) (0.5 O)0) 0.511-12) (0.5 O)1-0)5+0.5 O2 O2 O2 O2 O2 O2 O2 O2 O2 O2 O2 O2 O2 O2 O2 O2) (0.5 O2 O2 O2 O2 O2 O2 O2 O2 O2 O2 O2 O2 O2 O2 -0)5 O2 O2 O2 O2 O2 O2 O2 O2 O2 O2 O2 O2 O2 O2 O33.5 O2 O2 O2 O2 O2 O2 O2 O2 O2 O2 O2 O2 O2 O2 O1)2 O2 O2 O2 O2 O2 O2 O2 O2 O2 O2 O2 O2 O2 O2 011-12)2 O2 O2 O2 O2 O2 O2 O2 O2 O2 O2 O2 O2 O2 O2 (0.5 O2 O2 O2 O2 O2 O2 O2 O2 O2 O2 O2 O2 O2 O0)1 (0.5 O2)12)1 (0.5 O2)1 O)5 O)1 (0.5 O)1 (0.5 O1)5 O)1 (0.5 O)5 O0)1 (0.5 O) I2- 22.6 O and 1,-33.5 O 33.5 A
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The circuit diagram below shows two emf sources and a bulb connected in parallel. Also connected…

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