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Imani O'Neill
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Asked: 2022-05-18T20:09:07+00:00 In:

Solving the error: the given path’s format is not supported.

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I have the following csharp code, but I do not know how to find the correct result. Why has this problem occurred, and how can it be solved? Here is the code that I am running:

string str_uploadpath = Server.MapPath("/UploadBucket/Raw/");
 FileStream objfilestream = new FileStream(str_uploadpath +
  fileName, FileMode.Create, FileAccess.ReadWrite);

And this is the error text I receive:

The given path's format is not supported
the given path's format is not supported
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2 Answers

  1. Best Answer
    Expert

    The cause:

    You received the error ”the given path’s format is not supported” because you wanted to save a file to the file path. However, your filename was not exact because it contained some null characters, so the given format of path had no assistance.

    Solution:

    To solve this problem, let’s use System.IO.Path.Combine instead of str_uploadpath + fileName as the following:

    Path.Combine(str_uploadpath, fileName);

    A string will be returned.

    Or you can exclude the null characters from your file names by:

    public static string ToSafeFileName(this string s)
{
return s
.Replace("", "")
.Replace("/", "")
.Replace(""", "")
.Replace("*", "")
.Replace(":", "")
.Replace("?", "")
.Replace("<", "")
.Replace(">", "")
.Replace("|", "");
}

    And the operation is:

    Path.Combine(str_uploadpath, fileName.ToSafeFileName());
    Above are my suggestions. I hope it all goes well!!!
    • 0

  2. The error occurred when the filename was saved with an entire path. To get this error, you only need to have ":" in your file name. You should replace any ":" found in your file names (e.g. a date stamp). I.e: 

    string fullFileName = fileName.Split('.')[0] + "(" + DateTime.Now.ToString().Replace(':', '-') + ")." + fileName.Split('.')[1];
    • 11

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