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jaylonconroy
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Asked: 2022-07-30T00:42:41+00:00 In:

The solution for ”too few arguments to function c++” error?

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Good moring everybody.

I’m getting the ”too few arguments to function c++” error when running my program.

#include <stdio.h>

int sum(int a, int b, int c)
{
        return (a+b+c);
}
int main()
{
        int x,y,z;
        x = 10; y = 20; z = 30;

        printf("sum = %d\n", sum(x, y));
        printf("sum = %d\n", sum(x));
        printf("sum = %d\n", sum(10, 20));
 
        return 0;
}

And then it gives me the output:

prog.c: In function ‘main’:
prog.c:12:23: error: too few arguments to function ‘sum’
  printf("sum = %d\n", sum(x, y));
                       ^~~
prog.c:3:5: note: declared here
 int sum(int a, int b, int c)
     ^~~
prog.c:13:23: error: too few arguments to function ‘sum’
  printf("sum = %d\n", sum(x));
                       ^~~
prog.c:3:5: note: declared here
 int sum(int a, int b, int c)
     ^~~
prog.c:14:23: error: too few arguments to function ‘sum’
  printf("sum = %d\n", sum(10, 20));
                       ^~~
prog.c:3:5: note: declared here
 int sum(int a, int b, int c)
     ^~~
prog.c:9:10: warning: variable ‘z’ set but not used [-Wunused-but-set-variable]
  int x,y,z;
^

Can someone help me to fix the problem?

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1 Answer

  1. Expert

    The cause: This error happens because there are differing numbers of formal and actual arguments.

    Solution: You must check the total number of arguments while calling a function.

    #include <stdio.h>

int sum(int a, int b, int c)
{
        return (a+b+c);
}
int main()
{
        int x,y,z;
        x = 10; y = 20; z = 30;

        printf("sum = %d\n", sum(x, y, z));
        printf("sum = %d\n", sum(x,y,z));
        printf("sum = %d\n", sum(10, 20,30));

        return 0;
}

    Output:

    sum = 60
sum = 60
sum = 60
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