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Home/ Questions/Trial Using the given data, calculate the rate constant of this reaction.
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Asked: April 11, 20222022-04-11T19:11:51+00:00 2022-04-11T19:11:51+00:00In: Chemistry

Trial Using the given data, calculate the rate constant of this reaction.

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Trial Using the given data, calculate the rate constant of this reaction. [B] (M) 0.300 [A]...

Trial Using the given data, calculate the rate constant of this reaction.
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Rate & Rate Constant

Rate constant is a measure of the rate of reaction and the concentration of the substances which are reacting. It is believed to be proportionality constant when it is at a set temperature. The rate of reaction is determined by several variables, such as:

  • Temperature of environment.
  • The energy barrier that activates.
  • The concentration of species in aqueous solutions.
  • The area of the surface of a substance that is subject to reaction.
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    Robert Wilson
    2022-04-12T00:14:16+00:00Added an answer on April 12, 2022 at 12:14 am

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    Trial Using the given data, calculate the rate constant of this reaction. [B] (M) 0.300 [A]...

    {Equation: A+B – C + D Rate law: Rate = \[A[B]” Here, x is the order of the reaction wrtA y is the order of the reaction wrt B Experiment 1: 0.0112 M’s = $(0.390)*(0.300)” Experiment 2: 0.0645 M’s = Equation: A+B-C + D Rate law. Here, x is a measure of the reaction order wrtA. Experiment 1: 0.0112M’s = $(0.390),*(0.300),” Experiment 2 : 0.0645M’s = $ (0.390),*(0.720),” Experiment 3: 0.0190M’s = 0.0645M’s = 0.0390)*(0).720. Experiment 4 : 0.300) —-2 —-2 —-3 — — 2—-3 to determine the value of x. 0.0190 M’s (0.300), 0.0112 (0.390)* 0.300). 1.7 = (17.72 = (1.7), x = 1. 0.0645 M’s (0.390 (0.720) 0.0112 M/s K (03901″ (0.300) 5.8 = (2.4) 2.42 = (2.4) y = 2 Hence, the order of the reaction w.rt Bis 2 Therefore, the rate law is : Rate = k[A][B] Thus, order of the reaction = x + y = 2+1 = 3 Experiment 1:0.0112 M’s = (0.390)*(0.300) Rate law: Rate = k[A[B] Rate constant, k = [A][B] 0.0112 M/s (0.390 M) (0.300 M) = 0.319 M-:-|0.0645 Mis (0.720) 0.0112 K (03901″) 5.8 = (2.4), 2.42 = (2.4), y = 2, Experiment 1 :0.0112M’s = (0.390),*0.300) Rate law. Rate constant, Rate = [A][B] 0.0112M/s (0.300 M/s) 0.0390 M/s (0.300M) = 0.0319 M-:-}
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