Home/ Questions/Solving the error: typeerror float object cannot be interpreted as an integer
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Collin Roy
  • 27
Asked: 2022-05-16T08:44:15+00:00 In:

Solving the error: typeerror float object cannot be interpreted as an integer

  • 27

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I am trying to write a python that returns the invalid answer. I don’t know where the incorrect command is in the “typeerror float object cannot be interpreted as an integer”. My detail is:

from turtle import *
 
 speed(0)
 hideturtle()
 c = 450
 
 def grid(x,y,a):
  seth(0)
  pu()
  goto(x,y)
  pd()
  for i in range(4):
  forward(a)
  rt(90)
  for i in range(c/10):
  seth(0)
  forward(10)
  rt(90)
  forward(c)
  backward(c)
  for i in range(c/10):
  seth(0)
  rt(90)
  forward(10)
  rt(90)
  forward(c)
  backward(c)
  pu()
  goto(a+10,0)
  write("x")
  goto(0,a+10)
  write("y")
  pd()
 
 grid(0,0,c)
 grid(-c,0,c)
 grid(-c,c,c)
 grid(0,c,c)

and I end up with the warning message:

Traceback (most recent call last):
  File "C:\Users\nick\Desktop\gridv2.py", line 35, in <module>
  grid(0,0,c)
  File "C:\Users\nick\Desktop\gridv2.py", line 15, in grid
  for i in range(c/10):
 TypeError: 'float' object cannot be interpreted as an integer

Pls, suggest the best answer to fix it.

float object cannot be interpreted as an integer
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2 Answers

  1. Best Answer
    Expert

    The cause: 

    In:

    for i in range(c/10):

    The / is being used and as a result, you’re creating an effervescent float but not an integer.

    Solution:

    To fix this, use the int division operator.

    for i in range(c // 10):

     

    • 22

  2. range() is only compatible with integers. However, / can be used to divide integers. 

    >>> 450 / 10
45.0
>>> range(450 / 10)
Traceback (most recent call last):
 File "<stdin>", line 1, in <module>
TypeError: 'float' object cannot be interpreted as an integer

    Remake the value into an integer: 

    for i in range(int(c / 10)):

    Or, you can use the // floor operator: 

    for i in range(c // 10):
    • 19

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