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Home/ Questions/Error: valueerror: i/o operation on closed file - How to solve it?
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Arthur Courtois
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Arthur Courtois
Asked: May 11, 20222022-05-11T18:38:43+00:00 2022-05-11T18:38:43+00:00In: Programs

Error: valueerror: i/o operation on closed file – How to solve it?

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I don’t know what I’m doing wrong, but I’ve already lost a couple of days struggling with this. Here is my command line:

import csv 
 
 with open('v.csv', 'w') as csvfile:
  cwriter = csv.writer(csvfile, delimiter=' ', quotechar='|', quoting=csv.QUOTE_MINIMAL)
 
 for w, c in p.items():
  cwriter.writerow(w + c)

This returns:

ValueError: I/O operation on closed file.

I don’t have any experience with valueerror: i/o operation on closed file.. In this case, how should I change?

valueerror
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    Laura
    2022-05-24T07:47:14+00:00Added an answer on May 24, 2022 at 7:47 am

    This type of “ValueError: I/O operation on closed file” happens in two cases as follows:
    Case 1: When you try to write on a file after it has been closed using the close() statement. Here is the example:

    with open('v.csv','w') as file:
     file.write("Line 1.\n")
     file.write("Line 2.\n")
     file.close()
     file.write("One more line.")

    In the code above, when we try to write another statement into a file named “v.csv” after closing it, ValueError appears.

    Case 2:

    with open('v.csv','w') as file:
     file.write("Line 1.\n")
     file.write("Line 2.\n")
    
    file.write("One more line.")
    file.close()

    In the code above, we try to open and write something on a file named “v.csv”, and then close it. However, the “One more line” statement is used outside the with block. Therefore, the ValueError occurs because of incorrect indentation.

    Your issue is belong to Case 2, here is solution for it:

    with open('v.csv','w') as file:
     file.write("Line 1.\n")
     file.write("Line 2.\n")
     file.write("One more line.")
    file.close()

    Your “One more line” statement must be within the block.

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  2. Léna Remy
    2022-05-25T19:25:37+00:00Added an answer on May 25, 2022 at 7:25 pm

    The same error can be raised by Mixing: Tabs + Spaces.

    with open('/foo', 'w') as f:
     (spaces OR tab) print f <-- success
     (spaces AND tab) print f <-- fail
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  3. ferneparker
    2022-07-12T06:23:29+00:00Added an answer on July 12, 2022 at 6:23 am

    Your for statement must be within the block

    import csv    
    
    with open('v.csv', 'w') as csvfile:
        cwriter = csv.writer(csvfile, delimiter=' ', quotechar='|', quoting=csv.QUOTE_MINIMAL)
    
        for w, c in p.items():
            cwriter.writerow(w + c)

    The file is now closed except for the with block.

    >>> with open('/tmp/1', 'w') as f:
    ...     print(f.closed)
    ... 
    False
    >>> print(f.closed)
    True
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