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Home/ Questions/The easy way to handle error - warning: comparison between pointer and integer.
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Raya Williams
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Raya Williams
Asked: May 18, 20222022-05-18T16:05:51+00:00 2022-05-18T16:05:51+00:00In: c

The easy way to handle error – warning: comparison between pointer and integer.

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I’m building a new program, but when I run it, an error pops up. The error displayed is as follows:

warning: comparison between pointer and integer
  ('int' and 'char *')

I have tried several workarounds, but they still do not get the desired results. If you have come across this situation and have a solution for the “warning: comparison between pointer and integer” problem, please let me know. Here is what I do:

const char* message = "hi";
 
  //I then loop through the message and I get an error in the below if statement.
 
  if (*message == "\0") {
  ...//do something
  }

Thanks!

comparison between pointer and integer
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    dttutoria Expert
    2022-06-16T23:19:02+00:00Added an answer on June 16, 2022 at 11:19 pm

    The cause: The message “comparison between pointer (string) and integer (character)” indicates that you are attempting to make a comparison between a character and a string.

    Solution: In C, single characters are delimited by simple quotes, whereas strings are delimited by double quotations. Therefore, instead of:

    if (*message == "\0")

    you should write:

    if (*message == '\0')
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  2. Arthur Doucet
    2022-05-25T20:28:45+00:00Added an answer on May 25, 2022 at 8:28 pm

    This "\0" string is not a character. A character uses single quotes, like '\0'.

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