Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask question.(5)

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

ITtutoria

ITtutoria Logo ITtutoria Logo

ITtutoria Navigation

  • Python
  • Java
  • Reactjs
  • JavaScript
  • R
  • PySpark
  • MYSQL
  • Pandas
  • QA
  • C++
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Python
  • Science
  • Java
  • JavaScript
  • Reactjs
  • Nodejs
  • Tools
  • QA
Home/ Questions/What is the electric flux ?3 through the annular ring, surface 3?
Next
Answered
lyytutoria
  • 4
lyytutoriaExpert
Asked: April 10, 20222022-04-10T07:17:27+00:00 2022-04-10T07:17:27+00:00In: Physics

What is the electric flux ?3 through the annular ring, surface 3?

  • 4

. Advertisement .

..3..

. Advertisement .

..4..

......... ADVERTISEMENT .........

..8..

a) What is the electric flux ?3 through the annular ring, surface 3? (Express your answer...

a) What is the electric flux ?3 through the annular ring, surface 3? (Express your answer in terms of C, r1, r2, and any constants.)

b) What is the electric flux ?1 through surface 1? (Express ?1 in terms of C, r1, r2, and any needed constants.)

c) What is the electric flux ?2 passing outward through surface 2? (Express ?2 in terms of r1, r2, C, and any constants or other known quantities.)


♦ Relevant knowledge
In electromagnetism, the term “electric flux” is the measurement that the electrical field flows passing through the surface even though an electric field on its own is not able to flow. It’s a way to describe the electric field’s strength at any distance to the charge that causes the field.

electric fluxsurface
  • 2 2 Answers
  • 336 Views
  • 0 Followers
  • 0
Answer
Share
  • Facebook
  • Report

2 Answers

  • Voted
  • Oldest
  • Recent
  • Random
  1. Best Answer
    lyytutoria Expert
    2022-04-12T01:34:51+00:00Added an answer on April 12, 2022 at 1:34 am
    Concepts and Reason
    This problem can be solved using the concept of electric flux. Calculate the electric flux s3​ first
    Fundamentals
    The electric flux can be defined as the area covered by the electric field lines. The surface area will increase if there are more field lines crossing the surface. Mathematically, an electric flux can be described as the dot product from the electric field and the component of area perpendicular the field.
    • 8
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report
  2. tonytutoria
    2022-04-10T07:17:30+00:00Added an answer on April 10, 2022 at 7:17 am
    Concepts and Reason

    This problem can be solved using the concept of electric flux.

    Calculate the electric flux [katex]{s_3}[/katex] first

    Fundamentals

    The electric flux can be defined as the area covered by the electric field lines. The surface area will increase if there are more field lines crossing the surface.

    Mathematically, an electric flux can be described as the dot product from the electric field and the component of area perpendicular the field.

    The expression of electric flux ([katex]\phi [/katex])

    [katex]\begin{array}{c}\\\phi = E \cdot dA\\\\ = EdA\cos \theta \\\end{array}[/katex]

    E here is the electric field. A the area is the angle between the area element and the electric field.

    As a result of point charge Q, the electric field at position r is shown as follows:

    [katex]\vec E(r) = \frac{C}{{{r^2}}}\hat r[/katex]

    C here is the constant proportional charge.

    (a)

    The angle between surface 3 and the electric field is [katex]90^\circ [/katex].

    Here is the electric flux through the surface 3.

    [katex]{\phi _3} = \vec E(r)dA\cos \theta [/katex]

    Substitute [katex]90^\circ [/katex]

    [katex]\begin{array}{c}\\{\phi _3} = \vec E(r)dA\cos 90^\circ \\\\ = 0\\\end{array}[/katex]

    (b)

    The angle between surface 1 and the electric field is [katex]0^\circ [/katex]

    Here is the electric flux through the surface 1.

    [katex]{\phi _1} = {\vec E_1}(r)dA\cos \theta [/katex]

    Substitute [katex]0^\circ [/katex]

    [katex]\phi [/katex]1

    Here is the electric field for surface 1.

    [katex]\phi [/katex]2

    Here is the area element for surface 1.

    [katex]\phi [/katex]3

    Substitute [katex]\phi [/katex]4

    [katex]\phi [/katex]5

    (c)

    The angle between surface 2 and the electric field is [katex]0^\circ [/katex]

    Here is the electric flux through surface 2:

    [katex]\phi [/katex]7

    Substitute [katex]0^\circ [/katex]

    [katex]\phi [/katex]9

    Here is the electric field for surface 2.

    [katex]\begin{array}{c}\\\phi = E \cdot dA\\\\ = EdA\cos \theta \\\end{array}[/katex]0

    Here is the area element for surface 2.

    [katex]\begin{array}{c}\\\phi = E \cdot dA\\\\ = EdA\cos \theta \\\end{array}[/katex]1

    Substitute [katex]\begin{array}{c}\\\phi = E \cdot dA\\\\ = EdA\cos \theta \\\end{array}[/katex]2

    [katex]\begin{array}{c}\\\phi = E \cdot dA\\\\ = EdA\cos \theta \\\end{array}[/katex]3Ans Part a


    Part of

    Answer

    The electric flux through the surface 3 equals 0.

    Part b

    [katex]\begin{array}{c}\\\phi = E \cdot dA\\\\ = EdA\cos \theta \\\end{array}[/katex]4Part C is the electric flux through the surface 1.

    [katex]\begin{array}{c}\\\phi = E \cdot dA\\\\ = EdA\cos \theta \\\end{array}[/katex]4 is the electric flux through surface 2.

    • 13
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

Sidebar

Ask A Question
  • How to Split String by space in C++
  • How To Convert A Pandas DataFrame Column To A List
  • How to Replace Multiple Characters in A String in Python?
  • How To Remove Special Characters From String Python

Explore

  • Home
  • Tutorial

Footer

ITtutoria

ITtutoria

This website is user friendly and will facilitate transferring knowledge. It would be useful for a self-initiated learning process.

@ ITTutoria Co Ltd.

Tutorial

  • Home
  • Python
  • Science
  • Java
  • JavaScript
  • Reactjs
  • Nodejs
  • Tools
  • QA

Legal Stuff

  • About Us
  • Terms of Use
  • Privacy Policy
  • Contact Us

DMCA.com Protection Status

Help

  • Knowledge Base
  • Support

Follow

© 2022 Ittutoria. All Rights Reserved.

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.