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**Question 1:**What is the sign of ΔU as the system of ideal gas goes from point A to point B on the graph? (Hint the U is function of temperature only for a perfect gas)......... ADVERTISEMENT .........

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**Question 2:**How are Q and W related during the isochoric part of the overall path form state A to state D?......... ADVERTISEMENT .........

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**Question 3:**How are Q and W related during the isobaric part of the overall path for state D to state B?......... ADVERTISEMENT .........

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Question 1:Which option is correct?Because A and B have the same internal energy, delta U is also zero.

Explanation: PV = RT is the ideal gas. All terms are given their normal meanings. We can see that the PV values for A and B are the same from the plot. Therefore, T is the same in both cases. Because U is only a function T, there will not be any change to U during the process.

Question 2:Which option is correct?Q produces energy, while W is null.

Explanation: W = -PDV, so here to go from A to D. dV is zero. This means that there is no work. PV = RT. Since P is decreasing at constant voltage, so T will decrease, and extra heat will be released.

Question 3:Which option do you prefer?W is the energy output and Q the energy input. They are both equal in size.

Explanation: U is a state function and the value of U at A and B is equal. Q is lost when you go from A to D. Q will be gained when you go from D to B. Q will do work on the system, which will be the output.