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Home/ Questions/Which of the following hybridization schemes allows the central atom to form more than four bonds?
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kttutoria
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kttutoriaExpert
Asked: April 8, 20222022-04-08T07:04:53+00:00 2022-04-08T07:04:53+00:00In: Chemistry

Which of the following hybridization schemes allows the central atom to form more than four bonds?

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Question: Which hybridization scheme allows the central atom to form more than four bonds?


♦ Relevant knowledge
Hybridization refers to the combination of multiple atomic orbitals in order to produce atomic orbitals with identical shape, size, energy and orientations.

Example: When the carbon atom (C), joins four H atoms in bonding to form a CH4 molecular, the 2s orbital is mixed with three 2p orbitals, forming four new identical orbitals, called the four sp3 hybrid orbitals. Four sp3 hybrid orbitals are combined with four 1s orbitals made up of four H-atoms to create four identical C – H bonds.

Hybridization occurs because valence orbitals within different subshells have different energies, shapes, and that must be identical to form stable bonds to other atoms.

An orbital represents the movement electrons within a molecule. This approximation for simple hybridization is based upon the atomic orbitals. These are similar to the orbitals of the hydrogen atom. The Schrodinger equation is the only neutral atom that can be solved precisely. The atomic orbitals for heavier atoms like carbon, nitrogen, or oxygen are 2s, 2p, which is similar to the excited orbital status of hydrogen.

atombondshybridization scheme
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    kttutoria Expert
    2022-04-08T07:07:35+00:00Added an answer on April 8, 2022 at 7:07 am

    Here is my explain: The central atom must have more than four hybrid orbitals in the hybridization scheme to create more bonds. There are four hybrid orbitals in sp3, five hybrid orbitals in sp3d, and three hybrid orbitals within sp2. The sp3d combination scheme allows the central Atom to form more than 4 bonds.

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