The following article will add knowledge about “The reaction rate constant is determined to be 0.012 M^-1 s^-1. Ifafter 27 minutes the amount of A left is 0.048 M. What was the initial concentration of A? 0.049 2.53e16 0.72 19.49“. Let’s not forget to look at the content!

Question

The reaction rate constant is determined to be 0.012 M^-1s^-1. Ifafter 27 minutes the amount of A left is 0.048 M. What was the initial concentration of A?

0.049

2.53e16

0.72

19.49

Answer “The reaction rate constant is determined to be 0.012 M^-1 s^-1. Ifafter 27 minutes the amount of A left is 0.048 M. What was the initial concentration of A? 0.049 2.53e16 0.72 19.49”.

We have:

K = 0,012 M^-1s^-1 <- second order

1/A = 1/A₀ + kt

1/0,048M = 1/A₀ + (0,012 M^-1s^-1)(27min x 60s/min)

=> A₀ = 0,72M

So, the result of this question is 0.72.

Last words

Above is the solution of “The reaction rate constant is determined to be 0.012 M^-1 s^-1. Ifafter 27 minutes the amount of A left is 0.048 M. What was the initial concentration of A? 0.049 2.53e16 0.72 19.49“. If you have good solutions or comments, please leave a message.