I will be here to help you solve this type of problem today ” What is the solubility of M(OH)2 in pure water?”. Let’s follow each step carefully to know how to do and understand the way to solve this work in the most through way. To be able gain valuable knowledge, let’s concentrate on this.

Question: “What is the solubility of M(OH)2 in pure water?”

What is the solubility of M(OH)₂ in pure water?

Answer

To understand the thinking process and to complete the article, you can refer to the below.

When M(OH)₂ dissolves in water means dissociate into M²⁺ + OH^–. Let x mol/L has dissolved means xmol/L M²⁺ and 2xmol/L OH^– present in water.

K_sp = solubility constant

K_sp = [ M²⁺] [OH^–]2 (1)

Here. K_sp = 5.54 x10^-18

From (1) and putting values

5.54 x 10^-18 = x.(2x)²

5.45 x 10^-18 = 4x³

x³ = 1.36 x 10^-18

x= 1.109 x 10^-6 mol/l

x is solubility of M(OH)₂.

Relevant knowledge

The ability of a substance’s to dissolve in a solvent is called its solubility. Temperature can increase the solubility rate of a solvent. Ksp is the solubility constant.

Conclusion

This is how you solve this type of exercise “What is the solubility of M(OH)2 in pure water? ”. Please leave a message below if you have any questions or comments.

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