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Question

Part A

What magnetic field strength will levitate the 2.0 g wire in the figure? Assume the force of gravity is directed downwards in the image.

Express your answer using two significant figures.

B = _____ T

Part B

What direction should the magnetic field be pointed in order for the force on the wire to counteract gravity?

Answer “What magnetic field strength will levitate the 2.0 g wire in the figure? (figure 1)”.

Magnetic Field

A body with charge moves at a certain velocity and produces an electric field. The magnetic field can exert force on a body that is near it if the body gets close to it.

Answer and Explanation:

Given data:

Let’s first convert our data to a consistent set of units, such as S.I. units.

• The mass of the wire is: $m=2g=0.002k\mathrm{g.}$

• The current in the wire is: $I=1.5\mathrm{A.}$

• The length of the magnetic field is: $L=10cm=0.1m$

• Acceleration due to gravity: $g=$

Part A:

A magnetic field creates force when a charge moves in it. Since an electric current is made of moving charges, the force generated by an electric current in a magnet field (B), is

Because the wire is in a gravity field, you can set up a free body chart to determine its acceleration.  For a system in equilibrium we have

Here,

We are being asked to give the magnetic field values for two significant numbers.

B = 0.13T

Part B:

We find that the current is flowing in the opposite direction to the left. Therefore, using the right hand rule, the direction of magnetic field must be out of the page. To balance the gravitational force, it must be directed towards the reader.

Last words

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